0.024x^2+0.55x=0

Solution for 0.024x^2+0.55x=0 equation:

0.024x^2+0.55x=0

a = 0.024; b = 0.55; c = 0;
Δ = b2-4ac
Δ = 0.552-4·0.024·0
Δ = 0.3025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.55)-\sqrt{0.3025}}{2*0.024}=\frac{-0.55-\sqrt{0.3025}}{0.048}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.55)+\sqrt{0.3025}}{2*0.024}=\frac{-0.55+\sqrt{0.3025}}{0.048}
$